Calculator the amount of water produced by the combustion of 16g of hydrogen 

Asked by ranjitadas5013 | 30th Jul, 2019, 03:53: PM

Expert Answer:

straight H subscript 2 space plus space bevelled 1 half space straight O subscript 2 space rightwards arrow with heat on top space space straight H subscript 2 straight O 

According to the above equation one mole of H2 (2 g) on combustion gives one mole of water (18 g) 
now 16 gm of hydrogen,
1 space m o l e space o f space h y d r o g e n space equals fraction numerator g i v e n space m a s s over denominator m o l e c u l a r space m a s s end fraction space equals space 16 over 2 equals space 8 space m o l e s
sin c e space 1 space m o l e space o f space m e t h a n e space i s space g e t t i n g space u s e d space t o space f o r m space 1 space m o l e space o f space w a t e r space equals x over 18........ space m o l e c u l a r space m a s s space o f space w a t e r space i s space 18

therefore space 8 equals x over 18
x space equals space 18 cross times 8 space equals space 144 g

Answered by Ramandeep | 5th Aug, 2019, 03:44: PM