Calculate the number of lone pairs and bond pairs present in 1.1g of CO2. (Use N = 6 x 10^23)

44 g of CO₂ will have 6.022 x 10²³ molecules

1 g of CO₂ will have 6.022 x 10²³/44 molecules

So,

1.1 g of CO₂ = (6.022 x 10²³)/x 1.1/44 =  13.82 x 10²³ molecules

 1 molecule has 4 bond pairs.

So, 13.82 x 10²³ molecules will have 55 bond pairs.

Lone pairs wil be zero.