Calculate the number of lone pairs and bond pairs present in 1.1g of CO2. (Use N = 6 x 10^23)

Asked by Theodosia Lourdes | 19th Apr, 2011, 12:44: AM

Expert Answer:

44 g of CO2 will have 6.022 x 1023 molecules
1 g of CO2 will have 6.022 x 1023/44 molecules
So,
1.1 g of CO2 = (6.022 x 1023)/x 1.1/44 =  13.82 x 1023 molecules
 1 molecule has 4 bond pairs.
So, 13.82 x 1023 molecules will have 55 bond pairs.
Lone pairs wil be zero.

Answered by  | 19th Apr, 2011, 04:50: PM

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