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Calculate the molar conductance of 0.01M solution of an electrolyte which has a resistance of 210ohms at 298K. Cell constant is 0.88cm-1
Asked by mrudulmahadev1311 | 20 Aug, 2019, 20:40: PM
Given:
Resistance = 210 Ω
Concentration of solution = 0.1 M
Cell constant = 0.88 cm−1
Specific conductance
![equals fraction numerator Cell space constant over denominator Resistance end fraction
equals fraction numerator 0.88 over denominator 210 end fraction
space equals 0.00419 space ohm to the power of negative 1 end exponent space cm to the power of negative 1 end exponent](https://images.topperlearning.com/topper/tinymce/cache/b9a6ce90aca9ee9974850878c646bafc.png)
Molar conductance
![equals Specific space conductance cross times 1000 over straight C
space equals 0.00419 cross times fraction numerator 1000 over denominator 0.01 end fraction
space equals space 419.04 ohm space cm squared space mole to the power of negative 1 end exponent](https://images.topperlearning.com/topper/tinymce/cache/ff546de4abf7acfd9ebbebca31ff6694.png)
Answered by Varsha | 21 Aug, 2019, 11:04: AM
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