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Mole fraction of ch4 in a solution of 32g of ch4 and 256g of oxygen is?
Asked by atharvamane801 | 14 Jan, 2024, 12:07: PM
answered-by-expert Expert Answer

Dear Student,

Given mass of CHâ‚„ = 32g

Molar mass of CHâ‚„ = 16 g/mol

Moles of CHâ‚„ = Mass / Molar mass

Moles of CHâ‚„ = 32g / 16 g/mol ≈ 2 moles

Moles of Oâ‚‚:

Given mass of Oâ‚‚ = 256g

Molar mass of Oâ‚‚ = 32 g/mol

Moles of Oâ‚‚ = Mass / Molar mass

Moles of Oâ‚‚ = 256g / 32 g/mol = 8 moles

Total moles in the solution = Moles of CHâ‚„ + Moles of Oâ‚‚

Total moles = 2 moles + 8 moles = 10 moles

The mole fraction of CHâ‚„ = Moles of CHâ‚„ / Total moles = 2 moles / 10 moles = 0.2

 

So, the mole fraction of CHâ‚„ in the solution is 0.2.

 

Answered by | 16 Jan, 2024, 11:21: AM
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