JEE Class main Answered

Dear Student,

Given mass of CH₄ = 32g

Molar mass of CH₄ = 16 g/mol

Moles of CH₄ = Mass / Molar mass

Moles of CH₄ = 32g / 16 g/mol ≈ 2 moles

Moles of O₂:

Given mass of O₂ = 256g

Molar mass of O₂ = 32 g/mol

Moles of O₂ = Mass / Molar mass

Moles of O₂ = 256g / 32 g/mol = 8 moles

Total moles in the solution = Moles of CH₄ + Moles of O₂

Total moles = 2 moles + 8 moles = 10 moles

The mole fraction of CH₄ = Moles of CH₄ / Total moles = 2 moles / 10 moles = 0.2

So, the mole fraction of CH₄ in the solution is 0.2.