calculate the mass of 60% H2SO4 required to decompose 50g of CaCO3?

Asked by  | 7th Jun, 2011, 01:31: PM

Expert Answer:

The decomposition reaction :-
H2SO4 +CaCO3 ? CaCO3 + CO2 + H2O
1mol of sulphuric acid decomposes 1mol of calcium carbonate.
50g of calcium carbonate corresponds to 0.5mol of calcium carbonate.
Therefore,0.5mol of sulphuric acid is required to decompose 0.5mol of calcium
 carbonate.
0.5mol corresponds to 49g of H2SO4
As 60% of sulphuric acid is there, 60% of H2SO4 required =(100×49/60)g=81.67g
 
 

Answered by  | 10th Jun, 2011, 04:19: PM

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