Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

Calculate the freezing point depression expected for 0.0711m aqueous soln. of Na2SO4. If this solution
actually Freezes at -0.320c, what would be the value of van’t Hoff Factor (Kf For water is 1.86kkgmol-1
)U

Asked by Monikavyas097 | 29 Jun, 2021, 09:27: AM
Expert Answer
Depression of freezing point is calculated by-
increment straight T subscript straight f space equals straight i cross times straight m cross times straight K subscript straight f
0 minus left parenthesis negative 0.320 right parenthesis equals straight i cross times 0.0711 cross times 1.86
straight i equals fraction numerator 0.0711 cross times 1.86 over denominator 0.320 end fraction
straight i equals 0.413

Van apostrophe straight t space hoff space factor equals 0.413
Answered by Ravi | 02 Jul, 2021, 06:31: PM
CBSE 12-science - Chemistry
Asked by gauravrastogi577 | 16 Aug, 2022, 06:18: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by gauravrastogi577 | 16 Aug, 2022, 06:17: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by shiv.pama83 | 27 Nov, 2021, 05:50: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by mdarsadazizh | 31 Aug, 2021, 01:02: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by tejasdhaware509 | 02 Apr, 2021, 12:46: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by ravikumarmunnar2015 | 16 Nov, 2020, 08:59: PM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by Gaurav | 09 Nov, 2020, 12:30: AM
ANSWERED BY EXPERT
CBSE 12-science - Chemistry
Asked by 01abhishek072005 | 18 Sep, 2020, 10:08: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×