BD is the diagonal of a quad abcd in which AL is perpendicular to BD , CM IS perpendicular to BD show that area ABCD = half BD X ( AL + CM)

Asked by ayush kumar | 3rd Mar, 2011, 01:58: AM

Expert Answer:

Dear Student,
In the figure,
Area of ABCD= area of triangle ABD + area of triangle BCD
=(1/2 x AL x BD) + (1/2 x CM x B
Area of ABCD =1/2 BD (AL+CM)
Hence Proved
Team Topperlearning.

Answered by  | 2nd Mar, 2011, 10:50: PM

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