JEE Class main Answered
Figure shows the bead initially at a distance L/2 from left end of rod and rod ratates about an axis passing through left end .
Let us assume axis is perpendicular to plane of page.
Due to circular motion, bead experiences centrifugal force and moves towards right edge of rod.
when the bead is at a distance r from left end , centrifugal acceleration is
Above expression is written as
By integrating above expression from r = L/2 to r = L with initial condition v = 0 at x = L/2 ,
we get velocity of bead when it reaches right edge is
v = ω L
At the time of coming out of right edge , bead also has tangential velocity (ω L)
Hence, magnitude of the resultant velocity is √2 (ω L) as shown in figure