CBSE Class 11-science Answered
Answer 23rd ques plz
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Asked by lovemaan5500 | 07 Jan, 2019, 07:38: AM
Comparing given eqaution with standard equation ( y= Asin(ωt- kx)) of wave we get
Amplitude (A) = 1.2m
As we know angular frequency ω =2πf
So f = ω/2π = 3.5/2π = 0.56 Hz
Maximum velocity of particle = A×ω = 1.2× 3.5 = 4.2 ms-1
Answered by Ankit K | 07 Jan, 2019, 15:35: PM
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