An ore contains 1.24% of the mineral Argentine, by mass. How many grams of this ore would have to be processed in order to obtain 1.0g of pure solid silver?

Asked by susmita bhattacharjee | 1st Jun, 2013, 02:57: PM

Expert Answer:

1g of Ag  =    1
                ------    mole.
                   108
 
To get   1 mole of Ag, pure Ag2S needed is = 1 /2 m0le.
So, to get 1 / 108 mole Ag , pure Ag2S  needed would be  
 
1 / 216  mole       =     1
                            ------ x ( 2 x 108 + 32 g )     =   248   / 216   g
                              216
 
Ore needed  = 100      248   
                    ---- x ------
                     1.24    216
 
=          92.6g

Answered by  | 18th Jul, 2013, 03:38: PM

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