CBSE Class 11-science Answered
An object starts from rest moves in constant acceleration A upto its max velocity and then retards at B until it comes to rest Cal the max velocity and the displacement if the total time of journey is T
Asked by sahamamoni597 | 27 Jun, 2023, 01:00: AM
Let t1 be the time taken by object to reach maximum velocity vmax with uniform acceleration A .
Then we have, ![begin mathsize 14px style v subscript m a x end subscript space equals space A space cross times space t subscript 1 end style](https://images.topperlearning.com/topper/tinymce/cache/cbe82953a347846343a4d6c5ec5b4c3d.png)
![begin mathsize 14px style v subscript m a x end subscript space equals space A space cross times space t subscript 1 end style](https://images.topperlearning.com/topper/tinymce/cache/cbe82953a347846343a4d6c5ec5b4c3d.png)
![begin mathsize 14px style t subscript 1 space equals space v subscript m a x end subscript over A space end style](https://images.topperlearning.com/topper/tinymce/cache/d94a05ee0d64b8e235370cdc67f1a61d.png)
Let t2 be the time taken by object to come to rest starting from maximum velocity vmax with retardation B .
Then we have, ![begin mathsize 14px style v subscript m a x end subscript space equals space B space asterisk times space t subscript 2 end style](https://images.topperlearning.com/topper/tinymce/cache/9f935bf88bae0a47fb85cae8c88e1259.png)
![begin mathsize 14px style v subscript m a x end subscript space equals space B space asterisk times space t subscript 2 end style](https://images.topperlearning.com/topper/tinymce/cache/9f935bf88bae0a47fb85cae8c88e1259.png)
![begin mathsize 14px style t subscript 2 space equals space v subscript m a x end subscript over B end style](https://images.topperlearning.com/topper/tinymce/cache/37a0f0883cc702df65dbdffcace610fb.png)
From eqn.(1) and (2) , we get
![begin mathsize 14px style t subscript 1 plus t subscript 2 space equals space v subscript m a x space end subscript open parentheses 1 over A plus 1 over B close parentheses end style](https://images.topperlearning.com/topper/tinymce/cache/61377e63e4c11abe74570ac3a2aaa426.png)
It is given that , ![begin mathsize 14px style t subscript 1 space plus space t subscript 2 space equals space T end style](https://images.topperlearning.com/topper/tinymce/cache/733f9cde2703cdfa416555e78fbe5bfb.png)
![begin mathsize 14px style t subscript 1 space plus space t subscript 2 space equals space T end style](https://images.topperlearning.com/topper/tinymce/cache/733f9cde2703cdfa416555e78fbe5bfb.png)
Hence , we get
![begin mathsize 14px style T space equals space v subscript m a x end subscript open parentheses 1 over A plus fraction numerator 1 over denominator B space end fraction close parentheses space equals space v subscript m a x end subscript space cross times open parentheses fraction numerator A plus B over denominator A space B end fraction close parentheses end style](https://images.topperlearning.com/topper/tinymce/cache/d557989be98d4eebfc69b87690dccb9b.png)
Hence maximum speed is
![begin mathsize 14px style v subscript m a x end subscript space equals space T space cross times open parentheses fraction numerator A cross times space B over denominator A plus B end fraction close parentheses end style](https://images.topperlearning.com/topper/tinymce/cache/ef21ca671c38e0bf53d1ed0010cbfde1.png)
Answered by Thiyagarajan K | 27 Jun, 2023, 02:49: AM
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