An object is placed at 10 cm distance infront of a concave mirror of radius of curvature of 20 cm. Find the position,nature and magnification of the image.

Asked by av601070 | 27th May, 2019, 02:52: PM

Expert Answer:

u = - 10 cm 
f = R/2 
R = - 20 cm 
f = -20/2 = -10 cm 
 
By mirror formula, 
 
1 over f equals 1 over v plus 1 over u   
 
fraction numerator 1 over denominator negative 10 end fraction space equals space 1 over v plus fraction numerator 1 over denominator negative 10 end fraction
T h u s comma
fraction numerator begin display style 1 end style over denominator begin display style v end style end fraction space equals space fraction numerator begin display style 1 end style over denominator begin display style negative 10 end style end fraction minus fraction numerator 1 over denominator negative 10 end fraction
fraction numerator begin display style 1 end style over denominator begin display style v end style end fraction space equals space fraction numerator begin display style 1 end style over denominator begin display style negative 10 end style end fraction plus 1 over 10 space equals fraction numerator 0 over denominator negative 100 end fraction
T h u s comma space v space equals space infinity
 
Thus, an image will be formed at infinity. 
 
The nature of image formed is real, inverted and highly magnified.
 
As the image is formed at infinity, it is highly magnified image. 

Answered by Shiwani Sawant | 27th May, 2019, 03:42: PM