CBSE Class 12-science Answered
An electron moves in a circular orbit of radius 0.51A around a nucleus at a frequency of 6.8times10^(15)Hz .Estimate the magnetic field at the nucleus
Asked by bogarpradnya | 03 Mar, 2020, 08:42: AM
Expert Answer
Frequency, 
= 6.8 × 1015 Hz
= 6.8 × 1015 HzCurrent, I = e = 1.6 x 10-19 x 6.8 × 1015 =10.88 × 10-4 A =1.08 × 10-3 A
= 1.6 x 10-19 x 6.8 × 1015 =10.88 × 10-4 A =1.08 × 10-3 AMagnetic field at centre is,
Thus, B = 13.5 T
Answered by Shiwani Sawant | 03 Mar, 2020, 12:11: PM
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