ABCD is a trapezium with AB parallel to DC. A line parallel to AC intersect AB at X and BC at Y. Prove that ar(triangle ADX)= ar(triangle ACY).
Asked by Sthitaprajna Mishra | 4th Feb, 2014, 07:47: PM
We know that two triangles on the same base and between the same parallels are equal in area.
Consider the following figure.
In the above figure, triangle ADX and ACX are on the same base AX and between the parallels AB and DC.
Therefore, ar .,..(1)
Similarly, triangle ACX and ACY are on the same base AC and between the parallels XY and AC.
From equations (1) and (2), we have
Answered by | 5th Feb, 2014, 11:04: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number