AB and AC are two chords of a circle of radius 'r' units. if AB=2AC,and the length of the perpendicular from the center on these chords are 'a'and 'b' prove that 4b2=a2 + 3r2

Asked by  | 24th Feb, 2012, 09:55: AM

Expert Answer:

Answered by  | 28th Feb, 2012, 04:08: PM

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