AB and AC are two chords of a circle of radius 'r' units. if AB=2AC,and the length of the perpendicular from the center on these chords are 'a'and 'b' prove that 4b2=a2 + 3r2
Asked by
| 24th Feb, 2012,
09:55: AM
Expert Answer:
Answered by
| 28th Feb, 2012,
04:08: PM
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