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A transverse travelling wave represented by a equation: y = (1 cm) sin[2nx – 20πt]; where X is in meters and t is in seconds, is travelling on a string of mass per unit length 0.01 Kg/m. Find the kinetic energy (in mille joule) of a portion of the string of length equal to one wavelength. (Take : π² = 10)
Asked by siddhi.sristy | 21 Dec, 2023, 03:19: PM
answered-by-expert Expert Answer

Equation of travelling transverse wave in a string is

img ....................... (1)

where A is amplitude of wave , λ is wavelength and ω is angular frequency.

Given transverse wave in string is

img  .......................(2)

By comparing eqn.(1) and (2) , we get amplitude  A = 1 cm , wavelength λ = 1 m  and angular frequency ω = 20π rad/s

Energy of transverse wave

img

where μ = 0.01 kg/m is linear mass density , i.e., mass per unit length of the string

E = 0.5 × 0.01 × (0.01)2 × (20π)2 × 1  J  = 2 × 10-3 J = 2 mJ

Answered by Thiyagarajan K | 21 Dec, 2023, 04:37: PM
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