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A wave traveling from the left encounters a junction between the heavy string in which it moves and a lighter one. The incoming wave divides equally into a transmitted and reflected component. What is the ratio of densities of the string?
Asked by anaghaagarwal15 | 15 Mar, 2022, 05:15: PM
answered-by-expert Expert Answer
Amplitudes of reflected waves and transmitted waves are given as
 
begin mathsize 14px style A subscript r space equals space fraction numerator left parenthesis space v subscript 2 space minus space v subscript 1 right parenthesis over denominator left parenthesis space v subscript 1 space plus space v subscript 2 right parenthesis end fraction A subscript i space end subscript end style............................(1)
begin mathsize 14px style A subscript t space equals space fraction numerator 2 space v subscript 2 over denominator left parenthesis space v subscript 1 plus v subscript 2 right parenthesis end fraction A subscript i end style ..........................(2)
Where A denotes Amplitude of waves , subscript i denotes incident wave,
subscript r denotes reflected wave  and subscript t denotes transmitted wave.
 
v1 and v2 are velocities in string-1 and string-2 respectively.
 
If the incoming wave is divided equally into reflected and transmitted component means
intensities of reflected and transmitted components are equal.
 
Since intensity of wave is proportional square of amplitude , we get
 
Ar2  = At2
 
Using eqn.(1) and (2) in above expression , we get after simplification as
 
begin mathsize 14px style left parenthesis space v subscript 2 space minus space v subscript 1 space right parenthesis to the power of 2 space end exponent space equals space 4 space v subscript 2 end subscript superscript 2 end superscript end style
 
we get the following quadratic equation in v1 from above expression
 
begin mathsize 14px style v subscript 1 superscript 2 space minus space 2 space v subscript 1 v subscript 2 space minus space 3 space v subscript 2 superscript 2 space equals space 0 end style
 
we get v2 = 3 v1 as acceptable solution from above expression
 
velocity of wave in the string is given as
 
begin mathsize 14px style v space equals space square root of T over d end root end style
where T is tension in the string and d is linear mass density ( mass per unit length )
 
hence , v2 begin mathsize 14px style proportional to end style ( 1 / d)
begin mathsize 14px style fraction numerator v subscript 2 superscript 2 over denominator v subscript 1 superscript 2 end fraction space equals space d subscript 1 over d subscript 2 space equals space 9 end style
Answered by Thiyagarajan K | 15 Mar, 2022, 11:07: PM
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