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A stone is thrown upwards vertically. It has speed 10m/s when it reaches one half of its maximum height. Then find out how high it will rise?
Asked by udayanmazumder079 | 13 Jul, 2023, 09:21: PM
Maximum height hmax reached by the stone is

...................... (1)
where u is initial speed when the stone is thrown.

At half of maximum height , speed is 10 m/s .

Let us consider the equation of motion " v2 = u2 - 2 g h " , where u is initial speed and
v is speed after making the vertical displacement h .

If we substitute v = 10 m/s and h = (1/2)hmax in above equation of motion, then we get

.....................(2)
If we substitute hmax using eqn.(1) , above eqn.(2) becomes

From above expression, we get u2 = 200 m2 /s2

Hence , we get maximum height from eqn.(1) as

Answered by Thiyagarajan K | 14 Jul, 2023, 09:27: AM

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