NEET Class neet Answered
a solenoid 20cm long having 100 turns is carrying a current i. the magnetic field at its centre is 3.14 × 10^-2.;
Asked by kannammalkannammal195 | 13 Jun, 2022, 08:53: PM
Expert Answer
Magnetic field at centre of solenoid = ( μo n i ) , where μo = 4π×10-7 H/m is permeability of free space .
n is number of turns per unit length , n = 100 /.2 = 500 turns/m
i is current in A
if magnetic field at centre of solenoid is 3.14 × 10-2 T ≈ π × 10-2 T , then
( μo n i ) = 4π × 10-7 × 500 × i = π × 10-2 T
we get current i = 50 A
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