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CBSE Class 11-science Answered

<div>&nbsp;</div> <div> <table class="ML10" style="padding: 0px; margin: 0px 0px 0px 10px; border: 0px; outline: 0px; font-size: 14px; vertical-align: top; border-collapse: collapse; border-spacing: 0px; color: #555555; font-family: Lato, Arial, sans-serif; font-weight: bold; line-height: 20px; background: transparent;"> <tbody style="padding: 0px; margin: 0px; border: 0px; outline: 0px; vertical-align: baseline; background: transparent;"> <tr style="padding: 0px; margin: 0px; border: 0px; outline: 0px; vertical-align: baseline; background: transparent;"> <td style="padding: 0px; margin: 0px; border: 0px; outline: 0px; font-size: 14px; vertical-align: top; background: transparent;"> <div style="padding: 0px; margin: 0px; border: 0px; outline: 0px; vertical-align: baseline; background: transparent;">A small block of mass m kept on a rough inclined surface of inclination 'A' fixed in a elevator.The elevator goes up witha uniform velocity v and the block does not slide on the wedge.The work done by the force of friction in time t will be??</div> </td> </tr> </tbody> </table> </div>
Asked by Malavika Umesh | 18 May, 2015, 06:51: PM
Expert Answer
 
 
Distance travelled bythe elevator in 't' time is = vt
As the block does not slide on the wedge. So friction force, f= mg sinθ
Angle between d and f is (90 - θ)
Work done by the force friction on the block in time t will be = F.d
That is,
Work, W = Fd cos (90 - θ)
              = mg sin θ . vtsin θ 
             = mg vtsin2θ
Thus, the work done by the force of friction in time t will be mgvtsin2θ
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