a right circular is divided by a plane parallel to its base into small cone of volume V1 at the top and a frustum of volume V2 as second part at the bottom . if V1:V2=1:3, find the ratio of the height of the altitude of small cone and that of the frustum
Asked by Rishikesh Jadhav
| 9th Feb, 2014,
04:30: PM
Expert Answer:
Volume of smaller cone =
Volume of the frustum =
Given that,
That is,
Now consider the following diagram
Here, triangles ABC and ADE are similar triangles.
Thus, we have
Therefore, we have,
Substituting this value in the ratio of altitudes, we have

Volume of smaller cone =

Volume of the frustum =

Given that, 

That is,

Now consider the following diagram
Here, triangles ABC and ADE are similar triangles.
Thus, we have

Therefore, we have,


Answered by
| 14th Feb, 2014,
05:57: PM
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