CBSE Class 10 Answered
A resistance wire made from German silver has a resistance of 4.25 ohm. Calculate the resistance oi another wire, made from the same material such that its length increased by 4times and area decreased by 3times.
Asked by sudhma3u | 31 May, 2019, 07:12: AM
Initial resistance R=4.25Ω
![R equals fraction numerator rho l over denominator A end fraction](https://images.topperlearning.com/topper/tinymce/cache/10fc86e533b79876dcb0c868f3045bf7.png)
If length is made 4 times, the new length would be
![l to the power of apostrophe equals 4 l](https://images.topperlearning.com/topper/tinymce/cache/768fc95e30d62c6e77ff71bf6726ee56.png)
Area is made one- third of its initial value , new area would be
![A to the power of apostrophe equals A over 3
N e w space r e s i s tan c e space i s space g i v e n space b y
R to the power of apostrophe equals fraction numerator rho l to the power of comma over denominator A to the power of comma end fraction
R to the power of apostrophe equals fraction numerator rho 4 l over denominator begin display style bevelled A over 3 end style end fraction
R to the power of apostrophe equals fraction numerator 12 rho l over denominator A end fraction
R to the power of apostrophe equals 12 R
O n space s u b s t i t u t i n g space t h e space v a l u e space o f space R
R to the power of apostrophe equals 12 cross times 4.25
R to the power of apostrophe equals 12 cross times 4.25
R to the power of apostrophe equals 51 capital omega](https://images.topperlearning.com/topper/tinymce/cache/c6b5be0f855f85cb27a3f4ce03702f00.png)
Answered by Utkarsh Lokhande | 31 May, 2019, 08:19: AM
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