CBSE Class 11-science Answered
a particle starts with velocity 20 m/s with constant retardation of 4m/s^2.find distance travelled in 7 seconds
Asked by rahi7102005 | 20 May, 2021, 19:52: PM
Distance travelled with retardation is determined from the following relation
" S = ( u t ) - [ (1/2) a t2 ] "
where u is initial speed , t is time of travel and a is retardation
S = ( 20 × 7 ) - [ (1/2) × 4 × 7 × 7 ] = 42 m
Answered by Thiyagarajan K | 21 May, 2021, 08:23: AM
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