A particle is located at 5i^ +6j^ + 7k^ at t=0.. After 5 seconds, it is located at 2i^+5j^ +5k^. The magnitude of displacement of the particle in XY plane is: ???
Asked by nutankumari95074
| 11th Jun, 2022,
05:24: PM
Expert Answer:
Displacement = Final position - Initial position
Displacement = ( 2 
+ 5 
+ 5 
) - ( 5 + 6 + 7 ) = ( -3 - - 2 )
Magnitude of total displacement = 
Magnitude of displacement in x-y plane = 
+ 5 + 5 ) - ( 5 + 6 + 7 ) = ( -3 - - 2 )
Answered by Thiyagarajan K
| 11th Jun, 2022,
08:10: PM
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