CBSE Class 11-science Answered
A particle is located at 5i^ +6j^ + 7k^ at t=0.. After 5 seconds, it is located at 2i^+5j^ +5k^. The magnitude of displacement of the particle in XY plane is: ???
Asked by nutankumari95074 | 11 Jun, 2022, 05:24: PM
Expert Answer
Displacement = Final position - Initial position
Displacement = ( 2 + 5 + 5 ) - ( 5 + 6 + 7 ) = ( -3 - - 2 )
Magnitude of total displacement =
Magnitude of displacement in x-y plane =
Answered by Thiyagarajan K | 11 Jun, 2022, 08:10: PM
Concept Videos
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by dhanshreekansyakar | 09 Jan, 2024, 11:57: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by banhisikhapanda49 | 07 Nov, 2023, 10:42: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by preethiprithivi05 | 21 Feb, 2023, 09:28: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rk274268 | 05 Aug, 2022, 01:19: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Kattaithihaas | 24 Jul, 2022, 01:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by pawankumardas15492 | 22 Jul, 2022, 10:24: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by nutankumari95074 | 11 Jun, 2022, 05:24: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by kaziryan.05 | 13 Apr, 2022, 09:01: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by aditya000ghoderao | 19 Jan, 2022, 05:05: AM
ANSWERED BY EXPERT