CBSE Class 11-science Answered
a particle is displaced (3i + 4j) from (3j - 2k) under the action of force (i - j+k)N. the workdone by the force is ______ joule
Asked by vaddevenkatesulu56 | 26 Feb, 2024, 09:02: PM
Expert Answer
The particle is displaced from position r1 = (3j - 2k) to r2 = (3i + 4j)
Thus, displacement, s = (3i + 4j) - (3j - 2k) = (3i - j + 2k)
Force = i - j + k
Thus,
Work done, W = F.s = (i - j + k). (3i - j + 2k) = (3) + (1)+ (2) = 6 J (Since i.i = j.j = k.k =1)
Thus, the work done by the force is 6 J.
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