a number consists of two digits whose number is 9 if 27 is subtracted from the number the digits interchange their places find the number

Asked by singhmanya0406 | 21st Jan, 2021, 09:57: AM

Expert Answer:

 
Let the digit at the ten's place be x → the digit at the unit place be 9 - x.
 
Two digit number = 10x + 9 - x = 9x + 9
 
According to the condition, 
 
9x + 9 - 27 = 10(9 - x) + x 
→ 9x - 18 = 90 - 10x + x
→ 18x = 72
→     x = 6
 
So, the required number is 9(6) + 9 = 54 + 9 = 63

Answered by Yasmeen Khan | 21st Jan, 2021, 08:13: PM

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