CBSE Class 12-science Answered
A normal visioned woman whose father is color blind, married a normal visioned man. What are the probablities of her sons or daughters to be color blind. Explain with the help of punnets square
Asked by khairnardarshan57 | 26 Feb, 2019, 05:53: PM
Colourblindness is an X-linked recessive trait caused due to the defective allele on the X chromosome.
In this problem,
Since the father is colourblind, his genotype would be XcY.
Although the woman has colourblind father, her vision is normal. This implies that she is a carrier of the trait. Therefore, her genotype would be.
This carrier woman marries a man with a normal vision.
|
X |
Y |
Xc |
XcX Daughter: Carrier |
XcY Son: Colourblind |
X |
XX Daughter: Normal |
XY Son: Normal |
From the above Punnett square, we can deduce that 50% of the daughter are carriers while 50% are normal. 50% of the sons are colourblind while 50% are normal.
Answered by Sheetal Kolte | 26 Feb, 2019, 06:50: PM
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