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A girl of mass 40 kg jumps with a horizontal velocity of 5m/s onto a stationary cart with frictionless wheels.The mass of the cart is 3 kg.What is her velocity as the cart starts moving?Assume that there is no external unbalnaced force working in the horizontal direction.  
Asked by rufinusrath | 28 Oct, 2020, 12:44: PM
answered-by-expert Expert Answer
we need to apply momentum conservation to get the final speed of girl who jumped on the cart
 
Initial momentum = mass of girl × intial horizontal speed = 40 × 5 = 200 kg m/s
 
Momentum of girl and cart after jumping = ( 40 +3 ) × v  kg m/s
 
where v is the final speed of cart+Girl after jumping.
 
By conservation of momentum,  ( 40 +3 ) × v = 200  or  v = ( 200 / 43 ) m/s = 4.65 m/s
Answered by Thiyagarajan K | 28 Oct, 2020, 04:33: PM

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CBSE 9 - Physics
A girl of mass 40 kg jumps with a horizontal velocity of 5m/s onto a stationary cart with frictionless wheels.The mass of the cart is 3 kg.What is her velocity as the cart starts moving?Assume that there is no external unbalnaced force working in the horizontal direction.  
Asked by rufinusrath | 28 Oct, 2020, 12:44: PM
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