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A drunkard is walking along a straigt road. He takes 5 steps forward ans 3 steps backward followed by 5 steps forward and 3 steps backward ,and so on. Each step is 1 m long and takes 1 second.There is a pit on the road 11 m away from the starting point.The drunkard will fall into the pit after what time {s}
Asked by ayan1.chatterjee | 29 Jan, 2021, 09:20: AM
Let us assume 5 forward motion and 3 backward motion as one cycle.

Displacement for one cycle  = (5 - 3 ) m = 2 m

Time duration of one cycle = ( 5 +3 ) 8 seconds

Number of full cycles required for 11 m distance = 11 / 2 = 5

Hence movement towards the pit has 5 complete cycles and 1 m forward distance

Required time t = ( 5 × 8 ) + 1 = 41 seconds
Answered by Thiyagarajan K | 29 Jan, 2021, 09:42: AM

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