A dice is rolled 3 times, what is the probabilty of getting a no. greater than last no. each time?
Asked by | 13th Nov, 2009, 01:21: PM
The maximum number that we can get is 6 in the third roll.
Then, the second can have 5, 4, 3, 2.
and for each of these the first roll can have (4,3,2,1), (3,2,1), (2,1), (1).
Hence there are 4+3+2+1 = 10 ways.
Similarly if the third roll gives a number 5 then,
there are 6 ways.
Similarly if the third roll gives a number 4 then,
there are 3 ways.
Similary if the third roll gives a number 3 then there is only one way.
Hence the probability = 20/216 = 5/54.
Answered by | 13th Nov, 2009, 02:35: PM
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