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a current i= a + bsin(wt) is passed through moving coil galvanometer. the reading which it wil gave.?
Asked by raghnibharti | 11 Mar, 2024, 21:11: PM
answered-by-expert Expert Answer

If current varying with time is passed through moving coil galvanometer , it shows the average value .

If the current is " i(t) = a + b sin (ω t ) " , then dc current of magnitude a is super imposed by ac current ( b sin (ω t ) ).

Average of ac current part is zero . Hence we will get average of current " i(t) = a + b sin (ω t ) "  as  a .

Hence , moving coil galvanometer gives the average reading a

Answered by Thiyagarajan K | 12 Mar, 2024, 16:50: PM
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