A COMPOUND OF CARBON, HYDROGEN,& NITROGEN CONTAINS THESE ELEMENTS IN RATIO 9:1:3.5 CALCULATE EMPIRICAL FORMULA IF ITS MOLECULAR MASS IS 108, WHAT IS MOLECULAR FORMULA?
Asked by Ashish nandal | 9th May, 2014, 07:42: PM
Element
Mass ratio
Atomic mass
Relative Number of atoms
Simplest ratio
C
9
12
9/12 = 0.75
0.75X4=3
H
1
1
1/1=1
1X4=4
N
3.5
3.5
3.5/14=0.25
0.25X4=1
Empirical ratio = C3H4N
Empirical formula mass = (3x12)+(4x1)+14= 54
n= Molecular mass = 108 = 2
Empirical formula mass 54
Molecular formula = (empirical formula)2 = (C3H4N)2 = C6H8N2
Element |
Mass ratio |
Atomic mass |
Relative Number of atoms |
Simplest ratio |
C |
9 |
12 |
9/12 = 0.75 |
0.75X4=3 |
H |
1 |
1 |
1/1=1 |
1X4=4 |
N |
3.5 |
3.5 |
3.5/14=0.25 |
0.25X4=1 |
Empirical ratio = C3H4N
Empirical formula mass = (3x12)+(4x1)+14= 54
n= Molecular mass = 108 = 2
Empirical formula mass 54
Molecular formula = (empirical formula)2 = (C3H4N)2 = C6H8N2
Answered by Vaibhav Chavan | 12th May, 2014, 09:29: AM
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