CBSE Class 11-science Answered
A certain compound of Iridium has 39.8 % of Iridium by weight in it. If one mole of the compound contains 6 Chlorine atoms in it, what are
1)the minimum molar mass of the compound and
2)weight % of chlorine in it?
Asked by aruni_maiyer | 15 Jul, 2010, 03:43: PM
Expert Answer
Mass of irirdium = 39.8
Mass of chlorine = 60.2
Moles of iridium = 30.8 / 192 = 0.16
Moles of chlorine = 60.2 / 35.5 = 1.6
Dividing by 0.16 we get
Formula = IrCl10
Minimum molar mass of the compound = 192 + 355 = 547
Percentage weight of chlorine in it = 355 / 547 * 100 = 64.8 %
Answered by | 21 Jul, 2010, 05:20: PM
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