A certain compound of Iridium has 39.8 % of Iridium by weight in it. If one mole of the compound contains 6 Chlorine atoms in it, what are 1)the minimum molar mass of the compound and 2)weight % of chlorine in it?

Asked by aruni_maiyer | 15th Jul, 2010, 03:43: PM

Expert Answer:

Mass of irirdium = 39.8
Mass of chlorine = 60.2
Moles of iridium = 30.8 / 192 = 0.16
Moles of chlorine = 60.2 / 35.5 = 1.6
Dividing by 0.16 we get
Formula  = IrCl10
Minimum molar mass of the compound = 192 + 355 = 547
Percentage weight of chlorine in it = 355 / 547 * 100 = 64.8 %

Answered by  | 21st Jul, 2010, 05:20: PM

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