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A car starting from rest. is accelerated up to a distance S at a rate. and moves at a constant speed till time t. And after that the retardation rate becomes constant. If the total distance covered by it is equal to 15S, then find the value of S in terms 2 of f and t.
Asked by surabhilakhara7299 | 11 Jun, 2021, 05:19: PM
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A car, starting from rest, accelerates at a rate 'f' through a distance 's', then continues at a constant speed for sometime 't' and then decelerates at the rate 'f/2' to come to rest. If the total distance is '5s', then prove that s=1/2ft^2 or s=1/2f(t)square

Answered by Shiwani Sawant | 11 Jun, 2021, 06:09: PM
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A car starting from rest. is accelerated up to a distance S at a rate. and moves at a constant speed till time t. And after that the retardation rate becomes constant. If the total distance covered by it is equal to 15S, then find the value of S in terms 2 of f and t.
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