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3. A particle is moving on a circular path of radius 6 m. Its linear speed is v = Zt here t is time in v is in m/s. Calculate its centripetal acceleration at t =3: .
Asked by purabidey2001 | 07 Feb, 2024, 07:54: AM
answered-by-expert Expert Answer

linear speed at time t is ,  v(t) = Z t

linear speed at time t = 3 s is ,  v(3) = 3 Z m/s

Centripetal acceletaion = ( velocity)2 / ( radius of circular path )

Centripetal acceleration at t = 3 s is  (3Z)2/6 m/s2 = 1.5 Z2  m/s2

Answered by Thiyagarajan K | 07 Feb, 2024, 01:05: PM
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