A Box contains 3 white balls and 7 black balls.another box contains 4 white balls and 6 black balls.if we choose one ball from each boxes without looking into it a)probability of getting balls with colour B)probability of getting balls with different colours

Asked by  | 18th Mar, 2013, 08:00: AM

Expert Answer:

It seems like the first part of your question talks about the probability of getting balls with same color 
 
Let W1 and W2 be the event of drawing a while ball from first and second bag respectively.
Let B1 and B2 be the event of drawing a black ball from first and second bag respectively.
 
Prob(same color) = P(W1W2) + P(B1B2)
Prob(same color) = P(W1) *P(W2) + P(B1)*P(B2) = 3/10 *4/10 + 7/10*6/10 = 0.54
 
Prob(diff color) = P(W1B2) + P(B1W2)
Prob(diff color) = P(W1) *P(B2) + P(B1)*P(W2)  = 3/10*6/10 + 7/10*4/10 = 0.46

Answered by  | 18th Mar, 2013, 05:10: PM

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