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A body moving with uniform acceleration travels 24m in 6th second and 44 m in 11th second.Find the :(1) acceleration (2) initial velocity of the body ?
Asked by nishasaumitya | 23 May, 2018, 12:06: AM
Equations are to be used " S = u×t+(1/2)×a×t2 "  and " v = u + a×t " .
u and v are initial and final velocity respectively. a is acceleration, S is distance travelled and t is time.

24 m travelled in 6th second :-  u5+(1/2)a = 24  .......................(1)

where u5 is speed after 5 seconds and is given by,  u5 = u0+5a  ...................(2)

where u0 is initial velocity. Using eqns.(1) and (2) we can write   u0+(11/2)×a = 24 ......................(3)

44 m travelled in 11th second :- u10+(1/2)a = 44......................(4)

where u10 is the speed after 10 seconds and is given by   u10 = u0+10a  .....................(5)

using eqn.(4) and (5), we can write u0 +(21/2)a = 44 ..........................(6)

Solving eqns. (3) and (6) , we get a = 4 m/s2 and u0 = 2 m/s
Answered by Thiyagarajan K | 23 May, 2018, 11:37: AM

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