A body falling from the height of 10 m rebounds from the hard surface. It loses 20% of its energy in impact. What is the height to which it would raise after the impact and where this energy goes after hitting the surface?

Asked by Topperlearning User | 8th Jul, 2014, 10:45: AM

Expert Answer:

Let the potential energy of the body at height 10 m be mgh.

Let the potential energy after striking the surface be mgh'.
After striking the surface, it loses 20% of its energy.
Thus, its new potential energy is (100 - 20)% mgh = 80% mgh
Now, we have
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The energy is dissipated as heat after hitting the surface.

Answered by  | 8th Jul, 2014, 12:45: PM