A beam of light consisting of 2 wavelengths , 650 nm and 520 nm is used to obtain interference in YDSE . If bright fringes due to both the wavelengths coincide at any point P then least distance of P from central maxima is (slit separation is 2 mm and distance b/w slits and screen is 1.2 m)
1) 1.56 mm
2) 2.36 mm
3) 3 mm
4) 1.8 mm
Please explain the answer in detail.
Asked by Kb Aulakh | 25th Apr, 2015, 06:10: PM
Let the wavelength of the two beams be:
The least distance from central maxima is 1.56 mm
Answered by Jyothi Nair | 27th Apr, 2015, 03:17: PM
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