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a ball is tied at one end of a string, the other end is tied at the centre of the merry go round. if the string breaks, the person standing outside the merry go round will observe that the ball is moving in a straight line, whereas the person standing on the merry go round observes that the ball always remains in front of him radially away from him. explain the reason for each. how is centrifugal force acting in the second case?
Asked by saibaba1069 | 23 Mar, 2020, 10:58: PM
Figure shows the merry-go-round rotating in clockwise direction. A ball is attached to string and connected to rotation axis of merry-go-round.

An observer A standing on the merry-go-round, whereas observer B is watching the ball movement from ground i.e., outside the merry-go-round.

Vertical component of tension force balance the weight and horizontal tension force component gives centripetal force to the ball to go in circular motion.

To observer-B, the ball is seen to move in circular path due to centripetal force CP before breaking of string.

To observer-A, since his frame of reference is attached to merry-go-round, equivalent centrifugal force CF acting on the ball
so that ball appears to him stationary before breaking of string.

When the string is broken, since tension is absent, centripetal force vanishes. To Observer-B , the ball appears to move straight line
in tangential direction because just before breaking of string, observer-B see the ball moving tangentially on the circular path .

Whereas to observer-A, since just before breaking the ball is subjected to radial centrifugal force away from him,

he will view the ball moves radially outward from him
Answered by Thiyagarajan K | 24 Mar, 2020, 09:09: AM

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