A ball is dropped on the floor from a height of 10 metre rebounds to a height of 2.5 M if the ball is in contact with the floor for 0.01 seconds what is the average acceleration during contact
Asked by www.naresh | 4th Feb, 2018, 07:28: AM
The height from which the ball is dropped cannot be 10 cm, it will be 10 m as the ball is said to rebound 2.5 m.
Given, the height from which the ball is dropped, h1 =10 m,
The height to which the ball rebounds, h2 = 2.5 m
Time of contact of the ball with floor, Δt = 0.01 sec
Let v1 be the velocity of the ball when dropped before striking the floor,
v2 be the velocity of ball upwards after striking the floor during rebounding
Change in velocity of ball during contact =v2 - (-v1)
Average acceleration = 2100 m/s2
Answered by Abhijeet Mishra | 4th Feb, 2018, 04:12: PM
- Formula of momentum
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