a 1580kg car is travelling with a speed of 15.0ms-1 what is the magnitude of the horizontal net force that is required to bring the car to a halt in distance of 50.0m?

Asked by praju99 | 22nd Aug, 2010, 12:00: AM

Expert Answer:

Use,
v2 = u2 + 2as to find a.
a = -u2/2s = - 152/(2x50) = = - 2.25 m/s2   
Force = m x a = 1580 kg x - 2.25 m/s2 = - 3555 N
Negative sign is because the force is opposing the motion.
Regards,
Team,
TopperLearning.

Answered by  | 22nd Aug, 2010, 10:32: PM

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