CBSE Class 10 Answered
A block of mass 10 kg is placed on a horizontal surface is connected by a cord passing over a frictionless pulley to a hanging block of mass 10 kg. If the coefficient of friction between the block and the surface is 0.5 and g = 10 m/s^2, then find the accleration of the system.
Asked by acv27joy | 22 May, 2018, 07:35: PM
Expert Answer
For mass A: T- μm1g = m1a
→ T =m1a + μm1g...(1)
For mass B: m2 g - T = m2a
→ T =m2 g - m2a...(2)
From (1) and (2)
m1a + μm1g=m2 g - m2a
Thus, the acceleration of the system is 2.5 m/s2
Answered by Shiwani Sawant | 23 May, 2018, 04:06: PM
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