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ICSE Class 10 Answered

3x^3+2x^2-19x+6
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Asked by sprdivya97 | 16 Sep, 2018, 10:06: PM
answered-by-expert Expert Answer
For x = 2 
p(x) = 3x+ 2x- 19x + 6
p(2) = 0
Hence, x - 2 is a factor of p(x)
If you divide p(x) by x - 2 we get
3x+ 2x- 19x + 6 = (x - 2)(3x2 + 8x - 3)
                              = (x - 2)((3x - 1)(x + 3)
Answered by Sneha shidid | 17 Sep, 2018, 11:11: AM
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