3rd ques plz

Asked by lovemaan5500 | 29th Dec, 2017, 06:42: AM

Expert Answer:

Heat loss by M2 kg of steam, QS = M2×L+M2×C1*(100-t2)
 
Heat Gain by Calorimeter QC = M1×C1×( t- t1)
 
Heat Gain by Water  QW = M×C2×( t- t1)
 
QS = QC +QW

M2×L + M2×C1×(100 - t2) = M1×C1×(t2 - t1)+M×C2×( t- t1) = (M1×C1+M×C2)×[t- t1]
 
L = [ (M1/M2)×C1+( M / M2)×C2 ] ×(t- t1) - C1×( 100 - t2)

Answered by  | 29th Dec, 2017, 11:46: AM