CBSE Class 11-science Answered
30 ml of 0.2 N BaCl2 is mixed with 40 ml of 0.3 N Al2(SO4)3 . How many gram of BaSO4 is formed?
Asked by sonali garg | 23 Oct, 2014, 05:57: PM
Expert Answer
3 BaCl2 + Al2(SO4)3 → 3BaSO4 + 2AlCl3
mM before reaction 30x0.2 40 x0.3
=6 =12 0 0
mM after reaction 0 (12-1) 3 2
Since 6mM of BaCl2 reacts with one mole of Al2(SO4)3
So m M of BaSO4 formed = 3 = wt./ m. wt. x 1000
So Wt. of BaSO4 formed = 3 x 233 = 0.699 g
1000
Answered by Arvind Diwale | 26 Oct, 2014, 02:45: PM
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