2nd equation of motion

 

Asked by 8708490733kushagra1 | 18th Jul, 2019, 12:50: AM

Expert Answer:

Second equation of motion describes distance S travelled by a body in a time duration t seconds,
if it starts with initial velocity u and moving with constant acceleration a.
 
If initial velocity is u and final velocity after t seconds is v, then average velocity = (u+v)/2
 
distance S travelled in t seconds is given by,  S = [(u+v)/2]×t  ..................(1)
 
we have final velocity v as,  v = u+a×t  ....................(2)
 
where a is acceleration
 
By substituting v from eqn.(2) in eqn.(1), we get,  S = u×t + (1/2)a×t2  ..................(3)
 

Answered by Thiyagarajan K | 18th Jul, 2019, 11:50: AM

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