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2nd equation of motion
Asked by 8708490733kushagra1 | 18 Jul, 2019, 12:50: AM
Second equation of motion describes distance S travelled by a body in a time duration t seconds,
if it starts with initial velocity u and moving with constant acceleration a.

If initial velocity is u and final velocity after t seconds is v, then average velocity = (u+v)/2

distance S travelled in t seconds is given by,  S = [(u+v)/2]×t  ..................(1)

we have final velocity v as,  v = u+a×t  ....................(2)

where a is acceleration

By substituting v from eqn.(2) in eqn.(1), we get,  S = u×t + (1/2)a×t2  ..................(3)

Answered by Thiyagarajan K | 18 Jul, 2019, 11:50: AM

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