CBSE Class 11-science Answered
2.5 moles of sulphuryl chloride were dissolved in water to produce sulphuric acid and hydrochloric acid. How many moles of KOH will be required to completely neutralize the solution?
Asked by | 02 Aug, 2012, 12:30: PM
Expert Answer
SO2Cl2 + 2H2O ------> H2SO4 + 2HCl
Moles of HCl produced from 2.5 moles of SO2Cl2 = 5
Moles of H2SO4 produced from 2.5 moles of SO2Cl2 = 2.5
H2SO4 + KOH -----> K2SO4 + 2H2O
HCl + KOH -----> KCl + H2O
5moles of H2SO4 needs KOH = 10
2.5 moles of HCl needs KOH = 2.5
So, total KOH required = 12.5 moles
Answered by | 02 Aug, 2012, 06:41: PM
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