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CBSE Class 11-science Answered

2.5 moles of sulphuryl chloride were dissolved in water to produce sulphuric acid and hydrochloric acid. How many moles of KOH will be required to completely neutralize the solution?

 
i have a doubt regarding  answer being 7.5moles but the ans is 12.5mol in sureshot questions 
plzzzzzzzzz clarify it

Asked by Abhishikth | 23 Aug, 2015, 01:48: PM
answered-by-expert Expert Answer

Reaction for the formation of sulphuric acid and hydrochloric acid from sulphuryl chloride is as follows:

SO2Cl2 + 2H2O  → H2SO4 + 2HCl

Moles of HCl produced from 2.5 moles of SO2Cl2 = 5 moles

Moles of H2SO4 produced from 2.5 moles of SO2Cl2 = 2.5 moles

Neutralisation reactions are as follows:

H2SO4 + 2KOH → K2SO4 + 2H2O

HCl + KOH → KCl + H2O

5 moles of H2SO4 needs KOH = 10 moles

2.5 moles of HCl needs KOH = 2.5 moles

Hence, the total moles of KOH required = 12.5 moles

Answered by Prachi Sawant | 23 Aug, 2015, 06:51: PM
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