CBSE Class 11-science Answered
2.5 moles of sulphuryl chloride were dissolved in water to produce sulphuric acid and hydrochloric acid. How many moles of KOH will be required to completely neutralize the solution?
i have a doubt regarding answer being 7.5moles but the ans is 12.5mol in sureshot questions
plzzzzzzzzz clarify it
Asked by Abhishikth | 23 Aug, 2015, 01:48: PM
Expert Answer
Reaction for the formation of sulphuric acid and hydrochloric acid from sulphuryl chloride is as follows:
SO2Cl2 + 2H2O → H2SO4 + 2HCl
Moles of HCl produced from 2.5 moles of SO2Cl2 = 5 moles
Moles of H2SO4 produced from 2.5 moles of SO2Cl2 = 2.5 moles
Neutralisation reactions are as follows:
H2SO4 + 2KOH → K2SO4 + 2H2O
HCl + KOH → KCl + H2O
5 moles of H2SO4 needs KOH = 10 moles
2.5 moles of HCl needs KOH = 2.5 moles
Hence, the total moles of KOH required = 12.5 moles
Answered by Prachi Sawant | 23 Aug, 2015, 06:51: PM
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